# More Common Products

**Square of a Trinomial**

**Cube of a Binomial**

**Difference of Cubes**

**Sum of Cubes**

Here, we have four more commonly used polynomial product formulas from algebra that generalize the prior formulas for *common products*. The first formula is the **square of a trinomial** and is similar to the *square of a binomial* formula. The second formula is the **cube of a binomial**. It is like the *square of a binomial*, but to a higher exponent. The third formula is the **difference of cubes**, and it is simlar to the *difference of squares* formula. The fourth formula is the **sum of cubes**, and it can be derived directly the *difference of cubes* formula. All of the formulas are special cases of more general formulas that will be derived later.

### Derivations

**Square of a Trinomial**

For the first equality, we use the additive associative proerty to group **( b + c)** together. Then we apply the

*square of a binomial*formula with the terms

**and**

*a***(**to get the second equality. For the third equality, we apply the distributive property to turn

*b + c*)**into**

*2a*(*b + c*)**. Then another application of the**

*2ab + 2ac**square of a binomial*formula on the last term gives us the fourth equality. The fifth and final equality comes from rearranging the terms through additive commutativity.

**Cube of a Binomial**

Starting with the binomial cubed, we can break off one of the **( a + b)** terms by using the definition of exponents or the properties of exponents to get the first equality. For the second equality, we apply the

*square of a binomial*on

**(**squared. Distribute the

*a + b*)**(**for the third equality. Again, use the distributive property several times and use multiplicative commutativity to get the fourth equality. The fifth equality follows after some rearrangement using the additive commutativity property. Additive associativity allows us to group the terms for the sixth equality. Distributivity gives us the seventh equality. The eight and final equality follows from the fact that

*a + b*)**(**and

*2 + 1*) = 3**(**.

*1 + 2*) = 3**Difference of Cubes**

For the first equality, we apply the distributive property. Then a few more applications of distributivity give us the second equality, along with the multiplicative commutativity property and product of an additive inverse. The third equality follows from additive associativity and additive inverse of a sum. We can eliminate the middle terms because they are additive inverse to get the fourth equality. The fifth and final equality follows by the additive identity property.

**Sum of Cubes**

To get the first equality, we use the additive inverse of an additive inverse twice. The additive inverse of a product gives us the second equality. The third equality follows from the a change to subtraction notation and two applications of the additive inverse of a product. Using ** a** and

**in the difference of cubes formula gives us the fourth equality. Finally, the fifth and final equality follows from several applicaitons of both the additive inverse of an additive inverse and the additive inverse of a product.**

*-b*