Dynamic Array Allocation

[Fred]

Hi

Thanks for the great tutorial videos. I have a question about video 36: The following is from the video.
 
********************************************************
int ArraySize;
    cout<<"How many integer should be stored"<< endl;
    cin>>ArraySize;
    int *ipIntArray =new int[ArraySize];
    for (int i=0;i<ArraySize; ++i){
        cout<< "input the integer number "<<i+1<<" :"<<endl;
        cin>> ipIntArray;
    }
    for (int i=0;i<ArraySize; ++i){
        cout<<ipIntArray<<" ";
    }

    cout<<endl;
    delete [] ipIntArray;
***********************************************


 My question is in the loop, when allocating the array elements, why shouldn't we use the dereference operator, as we do for integers? I was expecting to have something like
cin>> *ipIntArray;
and
cout<<*ipIntArray<<" ";

Regards
Fred

[Michael Hall]

That's not quite right. The line

Code:

cin >> ipIntArray;

should be

Code:

cin >> ipIntArray[i];

The bracket and integer value, i, effectively "dereference" the ith element of the array. Use * when you have one element and the brackets when you have an array.

Mike

P.S. You should also use the bracket operator in your later output loop.